Question
Download Solution PDF8 सेमी × 6 सेमी × 4 सेमीच्या एका आयताकृती ठोकळ्यातून 8 सेमी उंची आणि 4 सेमी तळत्रिज्या असलेला शंकु कोरलेला आहे. तर वाया गेलेल्या सामग्रीची अंदाजित टक्केवारी काढा:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेली माहिती:
शंकू: उंची (h) = 8 सेमी, त्रिज्या (r) = 4 सेमी
आयताकृती ठोकळा: लांबी = 8 सेमी, रुंदी = 6 सेमी, उंची = 4 सेमी
वापरलेली संकल्पना:
शंकूचे घनफळ = 1/3πr2h,
आयताकृती ठोकळ्याचे घनफळ = लांबी × रुंदी × उंची
वाया गेलेल्या सामग्रीची टक्केवारी = ((ठोकळ्याचे घनफळ - शंकूचे घनफळ)/ठोकळ्याचे घनफळ) × 100%.
गणना:
⇒ शंकूचे घनफळ = 1/3π(4)2 × (8) = 134.041 सेमी3
⇒ ठोकळ्याचे घनफळ = 8 × 6 × 4 = 192 सेमी3
⇒ वाया = 192 - 134.041 = 57.959 सेमी3
⇒ वाया गेलेल्या सामग्रीची टक्केवारी = (57.959/192) × 100% ≈ 30%
म्हणून, वाया गेलेल्या सामग्रीची अंदाजित टक्केवारी 30% आहे.
Last updated on Jun 26, 2025
-> The Staff Selection Commission has released the SSC GD 2025 Answer Key on 26th June 2025 on the official website.
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