जर sec A = \(\frac{5}{4}\), तर \(\rm \frac{\tan A}{1 + \tan^2A} - \frac{\sin A}{\sec A}\)चे मूल्य आहे:

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Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 12 Dec 2022 Shift 4)

Answer 1

दिले:

sec A = \(\frac{5}{4}\)

वापरलेली संकल्पना:

sec²θ - tan²θ = 1

sinθ.secθ = tanθ

गणना:

\(\rm \frac{\tan A}{1 + \tan^2A} - \frac{\sin A}{\sec A}\)

⇒ \(\rm \frac{\tan A}{sec^2A} - \frac{\sin A}{\sec A}\)

⇒ \(\rm \frac{\tan A - sin\; A.sec\;A}{sec^2A}\)

⇒ \(\rm \frac{\tan A - tan\;A}{sec^2A}\)

⇒ \(\rm \frac{0}{sec^2A}\)

⇒ 0

∴ आवश्यक उत्तर 0 आहे.

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