Question
Download Solution PDFदिलेल्या आकृतीमध्ये, O हे वर्तुळाचे केंद्र आहे आणि ∠AOC = 140°. ∠ABC शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले:
O हे वर्तुळाचे केंद्र आहे
∠AOC =140°
गणना:
O हे वर्तुळाचे केंद्र आहे
उर्वरित चाप मध्ये D बिंदू घ्या
∠AOC = 140°
∠AOC = 2∠ADC (मध्यभागी जीवा द्वारे तयार केलेला कोन = समान चाप खंडात दोनदा कोन तयार होतो)
⇒ 140° = 2∠ADC
⇒ ∠ADC = 70°
ABCD हा चक्रीय चौकोन असेल
चक्रीय चौकोनाच्या विरुद्ध कोनांची बेरीज = 180°
⇒ ∠ABC + ∠ADC= 180°
⇒ 70° + ∠ABC = 180°
⇒ ∠ABC = 110°
∴ पर्याय 2 हे योग्य उत्तर आहे.
Last updated on Jul 12, 2025
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