The density of mercury used in shrinkage limit apparatus is ______ (approx).

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SSC JE Civil 10 Oct 2023 Shift 3 Official Paper-I
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  1. 15.6 g/cc
  2. 14.6 g/cc
  3. 13.6 g/cc
  4. 12.6 g/cc

Answer (Detailed Solution Below)

Option 3 : 13.6 g/cc
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Detailed Solution

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Explanation:

  • Specific gravity is also termed as relative density.
  • The relative density/specific gravity of a substance is defined as the ratio of the density, mass or weight of the substance to the density, mass or weight of water at 4°C
  • Specific gravity is the ratio of the specific weight of the liquid to the specific weight of a standard fluid.
  • In case of liquids standard fluid is taken as water with specific gravity 1.

\({\rm{\gamma }} = \frac{{{\rm{Density\;of\;Substance}}}}{{{\rm{Density\;of\;same\;volume\;of\;water}}}} = \frac{{\rm{\rho }}}{{{{\rm{\rho }}_{\rm{w}}}}}\)

The specific gravity of mercury is given as 13.6, which means that it is 13.6 times denser than water.

The density of water at 4°C is 1000 kg/m3. Therefore, the density of mercury at 4°C can be calculated as:

density of mercury = specific gravity x density of water at 4°C
density of mercury = 13.6 x 1000 kg/m3
density of mercury = 13600 kg/m3 = 13.6 g/cc

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