The velocity of a small ball of mass M and density d, when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is  \(\frac{d}{2}\), then the viscous force acting on the ball will be :

  1. 2Mg
  2. \(\frac{Mg}{2}\)
  3. Mg
  4. \(\frac{3}{2}\) Mg

Answer (Detailed Solution Below)

Option 2 : \(\frac{Mg}{2}\)
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Detailed Solution

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Concept:

Viscous force is the resistive force acting between the layers of the fluid. It opposes the relative motion of the layers.

This force is also known as fluid friction.

Calculation:

Let Fv be the viscous force and FB be the Bouyant force acting on the ball.

F1 Madhuri Others 03.08.2022 D1

Then, when body moves with constant velocity

Mg = FB + Fv [a = 0]

Fv = Mg – FB

=dVg - \(\frac{d}{2}\).Vg         (where, M = dVg  and V = volume of the ball )

=\(\frac{d}{2}\).Vg

Hence, FV = \(\frac{M}{2}g\)

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