The volume of rectangular block is 12288 m³. Its dimension are in the ratio of 4 : 3: 2. If the entire surface is polished at the rate 2 paise per m²,then find the total cost of polishing

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SSC CHSL Exam 2024 Tier-I Official Paper (Held On: 11 Jul, 2024 Shift 4)
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  1. Rs. 33.28
  2. Rs. 11.14
  3. Rs. 66.56
  4. Rs. 44.42

Answer (Detailed Solution Below)

Option 3 : Rs. 66.56
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Detailed Solution

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Given:

Volume of the rectangular block = 12288 m3

Dimensions ratio = 4 : 3 : 2

Rate of polishing = 2 paise per m2

Formula used:

Volume = length × breadth × height

Total Surface Area = 2(lb + bh + hl)

Total Cost of Polishing = Total Surface Area × Rate of Polishing

Calculation:

Let the dimensions be 4x, 3x, and 2x

Volume = 4x × 3x × 2x

⇒ 24x3 = 12288

⇒ x3 = 12288 / 24

⇒ x3 = 512

⇒ x = 8

Dimensions: 4x = 4 × 8 = 32 m, 3x = 3 × 8 = 24 m, 2x = 2 × 8 = 16 m

Total Surface Area = 2(lb + bh + hl)

⇒ Total Surface Area = 2(32 × 24 + 24 × 16 + 16 × 32)

⇒ Total Surface Area = 2(768 + 384 + 512)

⇒ Total Surface Area = 2(1664)

⇒ Total Surface Area = 3328 m2

Total Cost of Polishing = Total Surface Area × Rate of Polishing

⇒ Total Cost of Polishing = 3328 × 2

⇒ Total Cost of Polishing = 6656 paise

Convert paise to rupees:

⇒ Total Cost of Polishing = 6656 / 100

⇒ Total Cost of Polishing = Rs. 66.56

∴ The correct answer is option (3).

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