What is the escape velocity of earth?

  1. 11.2 Km/s
  2. 12.5 Km/s
  3. 11.8 Km/s
  4. 12.4 Km/s

Answer (Detailed Solution Below)

Option 1 : 11.2 Km/s
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 CONCEPT:

  • Escape velocity: The minimum velocity required to escape the gravitational field of the earth is called escape velocity. 
  • It is denoted by Ve.
  • The escape velocity on earth is given by:

\({V_e} = \sqrt {\frac{{2\;G\;M}}{R}} \)

Where M = mass of earth and R = radius of the earth

  • If a body of mass m placed on a surface inside a satellite moving around the earth. Then force on the body is

F2 P.Y 21.5.20 Pallavi D2

Explanation:

  • The lowest velocity which is required to escape the gravitational pull of the earth is called its escape velocity and it is 11.2 Km/s for Earth.
  • Different planets have different escape velocity depending on their mass and radius as shown above 

Additional Information

  • The escape velocity of Moon is 2.38 km/s
  • Among all the planet Jupiter has the highest escape velocity of 59.5 km/s.
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