A closed system undergoes a cycle consisting of two processes. Process 1 - 2 is an isothermal expansion whereas Process 2 - 1 is an isentropic compression. According to the first law of thermodynamics, which of the following statements is true for this cycle?

This question was previously asked in
SSC JE Mechanical 05 Jun 2024 Shift 2 Official Paper - 1
View all SSC JE ME Papers >
  1. Heat transfer during Process 1 - 2 is zero.
  2. Heat transfer during Process 2 - 1 is zero.
  3. Work done during Process 1 - 2 is zero.
  4. Work done during Process 2 - 1 is zero.

Answer (Detailed Solution Below)

Option 2 : Heat transfer during Process 2 - 1 is zero.
Free
RRB JE CBT I Full Test - 23
14.2 K Users
100 Questions 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

Concept:

In thermodynamic cycles, the first law of thermodynamics (energy conservation) states that the net work done by the system over one complete cycle is equal to the net heat added to the system. Let's analyze each process in the given cycle and determine the correctness of the statements.

Process 1 - 2: Isothermal Expansion

  • Isothermal Process: During an isothermal process, the temperature remains constant.
  • First Law of Thermodynamics: \(Q_{1-2} = W_{1-2}\)
  • Since the internal energy change ( \(\Delta U\) ) for an isothermal process of an ideal gas is zero (as \(\Delta T = 0\) ), the heat transfer ( \(Q_{1-2}\) ) is equal to the work done ( \(W_{1-2}\) ).
  • Therefore, heat transfer during Process 1 - 2 is not zero. Also, work done during Process 1 - 2 is not zero.

Process 2 - 1: Isentropic Compression

  • Isentropic Process: During an isentropic process, the entropy remains constant, and the process is adiabatic (no heat transfer).
  • First Law of Thermodynamics: \(Q_{2-1}\) = 0
  • For an isentropic process, the heat transfer ( \(Q_{2-1}\) ) is zero. However, there is work done during this process ( \(W_{2-1}\) ) since the system is being compressed.
  • Therefore, heat transfer during Process 2 - 1 is zero, but work done during Process 2 - 1 is not zero.

Conclusion

Based on the analysis of the processes:2) Heat transfer during Process 2 - 1 is zero.

Latest SSC JE ME Updates

Last updated on May 28, 2025

-> SSC JE ME Notification 2025 will be released on June 30. 

-> The SSC JE Mechanical engineering application form will be available from June 30 to July 21. 

-> SSC JE 2025 CBT 1 exam for Mechanical Engineering will be conducted from October 2 to 31. 

-> SSC JE exam to recruit Junior Engineers in different disciplines under various departments of the Central Government.

-> The selection process of the candidates for the SSC Junior Engineer post consists of Paper I, Paper II, Document Verification, and Medical Examination.

-> Candidates who will get selected will get a salary range between Rs. 35,400/- to Rs. 1,12,400/-.

-> Candidates must refer to the SSC JE Previous Year Papers and SSC JE Civil Mock Test, SSC JE Electrical Mock Test, and SSC JE Mechanical Mock Test to understand the type of questions coming in the examination.

Get Free Access Now
Hot Links: teen patti master gold download teen patti master 2025 teen patti teen patti joy teen patti real cash 2024