Question
Download Solution PDF6 সেমি × 8 সেমি × 5 সেমি এবং ওজন 1.92 N (g = 10m/s2 ব্যবহার করুন) আকারের কাঠের একটি টুকরোর ঘনত্ব (kg/m3 এ) নির্ণয় করুন।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFধারণা:
ঘনত্ব:
- ঘনত্ব হল একটি উপাদান কতটা দৃঢ়ভাবে একত্রে ধরে রাখা হয় তার একটি পরিমাপ।
- এটি প্রতি একক আয়তনের ভর হিসাবে সংজ্ঞায়িত করা হয়।
গাণিতিকভাবে, \(\rho =\frac{Mass}{Volume}\)
গণনা:
প্রদত্ত:
কাঠের মাত্রা = 6 সেমি × 8 সেমি × 5 সেমি, ওজন = 1.92 N, g = 10 m/s2
ওজন = ভর × মাধ্যাকর্ষণ
⇒ 1.92 = ভর × 10
⇒ \(mass=\frac{1.92}{10}=0.192~kg\)
∵ঘনত্ব, ρ = \(\frac{Mass}{Volume}\)
⇒ ρ = \(\frac{0.192}{0.06~\times~0.08~\times~0.05}\)
⇒ ρ = 800 kg/m3
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