Chetan travels from City A to City B. If Chetan drives his car at \(\frac{3}{4}\) of his normal speed, then he reaches City B 33 minutes late. Find the time (in minutes) that Chetan would have taken to travel from City A to City B if he drove at his normal speed.

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This question was previously asked in

SSC GD Constable 2025 Official Paper (Held On: 05 Feb, 2025 Shift 3)

Answer 1

Given:

When Chetan drives at (3/4) of his normal speed, he reaches City B 33 minutes late.

Let the normal time taken to travel from City A to City B be T (in minutes).

Calculation:

If speed is reduced to (3/4) of the normal speed, time increases by 33 minutes:

\(\dfrac{\text{Distance}}{\text{(Normal Speed)}} + 33 = \dfrac{\text{Distance}}{\text{(3/4 × Normal Speed)}}\)

⇒ \(\dfrac{\text{Distance}}{\text{Normal Speed}} + 33 = \dfrac{4}{3} \times \dfrac{\text{Distance}}{\text{Normal Speed}}\)

⇒ \(\dfrac{T + 33}{T} = \dfrac{4}{3}\)

⇒ \(\dfrac{33}{T} = \dfrac{1}{3}\)

⇒ T = 99 minutes

∴ The correct answer is option (1).

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