दोन शहरे A आणि B एका सरळ मार्गावर 135 किमी अंतरावर आहेत. एक कार A पासून सकाळी 8 वाजता सुरू होते आणि B च्या दिशेने 25 किमी/ताशी प्रवास करते. दुसरी कार सकाळी 9 वाजता B पासून सुरू होते आणि 30 किमी/ताशी वेगाने A च्या दिशेने जाते. ते किती वाजता भेटतील?

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SSC CGL 2022 Tier-I Official Paper (Held On : 09 Dec 2022 Shift 1)
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  1. सकाळी 11 वा
  2. सकाळी 10 वा
  3. सकाळी 10.45 वा
  4. सकाळी 11.30 वा

Answer (Detailed Solution Below)

Option 1 : सकाळी 11 वा
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बरोबर उत्तर आहे (a.11m)

महत्त्वाचे मुद्दे -

समजा ते सकाळी 8 नंतर x तासांनी भेटतात

x तासांनंतर A ने व्यापलेले अंतर = 25x किमी.

(x-1) तासांनंतर B ने कापलेले अंतर = 30(x-1) किमी.

\(अंतर = वेळ * वेग\)

135 = 25x + 30(x-1)

135 = 25x + 30x - 30

135 = 55x - 30

135 + 30 = 55x

१६५/५५ = x

म्हणजे, x = 3 तास

दोन गाड्या 3 तासांनंतर भेटतील; सकाळी ८ वाजता + ३ तास = सकाळी ११

त्यामुळे बरोबर उत्तर सकाळी ११ वाजता आहे

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