Question
Download Solution PDFఒకవేళ ఒక ఇటుక యొక్క ఘనపరిమాణం 0.0014 మీ3 అయితే, అప్పుడు 14 మీటర్ల పొడవు, వెడల్పు 0.125 మీటర్లు మరియు ఎత్తు 5 మీటర్ల ఎత్తు ఉన్న గోడను నిర్మించడానికి ఎన్ని ఇటుకలు అవసరం అవుతాయి?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చింది:
ఒక ఇటుక యొక్క ఘనపరిమాణం = 0.0014 మీ3
గోడ పొడవు = 14 మీ; గోడ వెడల్పు = 0.125 మీ
మరియు గోడ ఎత్తు = 5 మీ
ఉపయోగించిన ఫార్ములా:
గోడ యొక్క ఘనపరిమాణం = L × B × H
ఇటుకల సంఖ్య = గోడ యొక్క ఘనపరిమాణం/ఇటుక యొక్క ఘనపరిమాణం
ఎక్కడ, L = పొడవు; B = వెడల్పు; H = ఎత్తు
గణన:
గోడ యొక్క ఘనపరిమాణం = 14 × 0.125 × 5 = 8.75 మీ3
ఇటుకల సంఖ్య = 8.75/0.0014
⇒ 6250
∴ సరైన సమాధానం 6250.
Last updated on Jul 19, 2025
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