∆ABCలో, ∠CAB యొక్క సమద్విఖండనం BCని D వద్ద మరియు ∆ABC యొక్క చుట్టుకొలత E వద్ద కలుస్తుంది. ఒకవేళ AC : AE = 4 : 7, అప్పుడు AD : AB నిష్పత్తి ఎంత అవుతుంది?

  1. 7 : 4
  2. 5 : 4
  3. 4 : 7
  4. 3 : 2

Answer (Detailed Solution Below)

Option 3 : 4 : 7
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Detailed Solution

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F1 P.S Pallavi 28.11.19 D 11

AE అనేది ∠CAB యొక్క కోన సమద్విఖండన రేఖ .

⇒ ∠EAB = ∠CAE

అలాగే ∠CBA = ∠CEA ( వృత్తంపై జ్యా AC ద్వారా కోణాలు ఉపసంహరించబడతాయి)

⇒ ∆AEC ~ ∆ABD

⇒ AC/AE = AD/AB = 4/7

⇒ AD : AB = 4 : 7

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