The area of a sector of a circle is 66 cm2 and the angle of the sector is 60°. Find the radius of the circle.

This question was previously asked in
SSC CGL 2022 Tier-I Official Paper (Held On : 03 Dec 2022 Shift 1)
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  1. 5\(\sqrt15\) cm
  2. 6\(\sqrt14\) cm
  3. 7\(\sqrt19\) cm
  4. 3\(\sqrt14\) cm

Answer (Detailed Solution Below)

Option 4 : 3\(\sqrt14\) cm
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Detailed Solution

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Given:

The area of a sector of a circle is 66 cm2 and the angle of the sector is 60°

Concept used:

Area of a sector = πr2 × θ/360°

θ = angle of the sector

r = radius

Calculation:

According to the question,

\(\rm\frac{60^o}{360^o} × π r^2\) = 66

⇒ πr2 = 66 × 6

⇒ 22/7 × r2 = 6 × 11 × 6

⇒ r2 = 126

⇒ r = 3\(\sqrt14\) cm

So, radius = 3\(\sqrt14\) cm

∴ The radius of the circle is 3\(\sqrt14\) cm.

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