The Bell-Coleman cycle is an example of _________.

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  1. Brayton cycle.
  2. vapour compression refrigeration cycle 
  3. vapour absorption refrigeration cycle
  4. air refrigeration cycle

Answer (Detailed Solution Below)

Option 4 : air refrigeration cycle
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Explanation:

A Bell-Coleman air refrigeration cycle works on the reverse Brayton cycle.

F3 S.S Madhu 11.01.20 D6             F1 Vishamber 01-10-21 Savita Corrected

The relationship between the various temperature of the cycle is given by the isentropic relationship applied to both compression and expansion processes:

\({r_p} = \frac{{{P_2}}}{{{P_1}}} = {\left( {\frac{{{T_2}}}{{{T_1}}}} \right)^{\frac{\gamma }{{\gamma - 1}}}} = {\left( {\frac{{{T_3}}}{{{T_4}}}} \right)^{\frac{\gamma }{{\gamma - 1}}}}\)

\(\frac{{{T_2}}}{{{T_1}}} = \frac{{{T_3}}}{{{T_4}}}\;or\;\frac{{{T_2}}}{{{T_3}}} = \frac{{{T_1}}}{{{T_4}}}\)

\({\rm{COP}} = \frac{{{\rm{Refrigeration\;effect}}}}{{{\rm{Net\;work\;input}}}} = \frac{{{\rm{Heat\;added}}}}{{{\rm{Net\;work\;input}}}}\)

Refrigeration effect: Q1 = Cp(T1 – T4)

Compressor work, W= Cp(T2 – T1)

Turbine work, W= Cp(T3 – T4)

\(COP = \frac{{{Q_1}}}{{{W_1} - {W_2}}} = \frac{{\left( {{T_1} - {T_4}} \right)}}{{\left( {{T_2} - {T_1}} \right) - \left( {{T_3} - {T_4}} \right)}} = \frac{{\left( {{T_1} - {T_4}} \right)}}{{\left( {{T_2} - {T_3}} \right) - \left( {{T_1} - {T_4}} \right)}} = \frac{1}{{\frac{{{T_2} - {T_3}}}{{{T_1} - {T_4}}} - 1}}\)

\(COP = \frac{1}{{\frac{{{T_2} - {T_3}}}{{{T_1} - {T_4}}} - 1}} = \frac{1}{{\frac{{{T_3}}}{{{T_4}}}\left( {\frac{{\frac{{{T_2}}}{{{T_3}}} - 1}}{{\frac{{{T_1}}}{{{T_4}}} - 1}}} \right) - 1}} = \frac{1}{{\frac{{{T_3}}}{{{T_4}}} - 1}} = \frac{1}{{{{\left( {{r_p}} \right)}^{\frac{{\gamma - 1}}{\gamma }}} - 1}}\)

\(COP = \frac{1}{{{{\left( {{r_p}} \right)}^{\frac{{\gamma - 1}}{\gamma }}} - 1}}\)

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